2^2x^2+2x=(1/4)^2x-40

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Solution for 2^2x^2+2x=(1/4)^2x-40 equation: 



2^2x^2+2x=(1/4)^2x-40

We move all terms to the left:

2^2x^2+2x-((1/4)^2x-40)=0



Domain of the equation: 4)^2x-40)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2^2x^2+2x-((+1/4)^2x-40)=0

We add all the numbers together, and all the variables

2x+2^2x^2-((+1/4)^2x-40)=0

We multiply all the terms by the denominator


2x*4)^2x-40)+2^2x^2*4)^2x-40)-((+1=0

Wy multiply elements

32x^3=0

We do not support expression: x^3

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